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gayaneshka [121]
3 years ago
6

The population of a small town can be modeled by the exponential function p=14,512(1.03)t, where t is the number of years after

2005.
What is the significance of the value of 14,512
Mathematics
2 answers:
Ber [7]3 years ago
8 0
Hahahshxhchxhdhsbsbbsshhs
Rom4ik [11]3 years ago
4 0

Answer:

the significant value of this is the number of people the town started with.

Step-by-step explanation:

the 1.03 is how much the population increased per year after

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Somebody please help me with this !!!
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Step-by-step explanation:

Case 1 :

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Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

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A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti
jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

\pi = \frac{0.438 + 0.642}{2} = 0.54

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}

0.08\sqrt{n} = 1.96\sqrt{0.54*0.46}

\sqrt{n} = \frac{1.96\sqrt{0.54*0.46}}{0.08}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.54*0.46}}{0.08})^{2}

n = 12.21

Rounding up

We need a sample of size at least 13.

3 0
3 years ago
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