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rewona [7]
3 years ago
10

I need to solve (6x-7)^2=-75

Mathematics
2 answers:
Burka [1]3 years ago
8 0
Your answer will be a complex solution

6x-7=75i
6x=7-75i
x=7/6-75/6i
Degger [83]3 years ago
7 0
6x²-7²=-75 would be the answer
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A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
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Answer:

Approximately 24–36 pounds

Step-by-step explanation:

Given:

Weight of standard American Eskimo dog has mean= 30 pounds

A standard deviation= 2 pounds

For 99.7% of the dogs according to normal distribution would lie between 3 standard deviations on either side of the mean.

i.e. lower bound= Mean- 3 (standard deviation)

= 30-3(2)

=30-6

=24

Upper bound = Mean +3 (standard deviation)

= 30+3(2)

=30+6

=36

Hence the range of weights : 24-36 pounds

correct answer Approximately 24–36 pounds!

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Graham spent a total of $15.05 on 10 apples and a packet of strawberries. If a packet of strawberries cost $2.55, how much did e
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Step-by-step explanation:

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2 years ago
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Write the standard equation of a circle with center (-4 0) and radius 3 brainly
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(x-4)^2+(y-0)^2=3^2 is the answer
8 0
3 years ago
Please help!!! asap
MakcuM [25]

Answer: y = x^2 + 6x+ 9 = 0. (X+3)^2= 0 when x=3. This has one root.

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Step-by-step explanation:

6 0
3 years ago
Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f
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There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\

Subtracting Eqn 3 from Eqn 1;

(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5

Putting value of y in Eqn 1;

300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

  • brainly.com/question/5047646
  • brainly.com/question/5048216

#LearnwithBrainly

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3 years ago
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