3 years ago

What’s the value of k?

1 answer:

5 0

First of you need to find the formula for them and them equal it to eachother. Then solve for k. So try and find the slope and then the y int for g(x) is 20 and the y int for f(x) is 4 just find the slope and you should be fine

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Step-by-step explanation:

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Step-by-step explanation:

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MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

Read 2 more answers