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Scilla [17]
3 years ago
12

Let H be an upper Hessenberg matrix. Show that the flop count for computing the QR decomposition of H is O(n2), assuming that th

e factor Q is not assembled but left as a product of rotators.
Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

Answer is explained in the attached document

Step-by-step explanation:

Hessenberg matrix- it a special type of square matrix,there there are two subtypes of hessenberg matrix that is upper Hessenberg matrix and lower Hessenberg matrix.

upper Hessenberg matrix:- in this type of matrix  zero entries below the first subdiagonal or in another words square matrix of n\times n is said to be in upper Hessenberg form  if ai,j=0

for all i,j with i>j+1.and upper Hessenberg matrix is called unreduced if all subdiagonal entries are nonzero

lower Hessenberg matrix:-  in this type of matrix  zero entries upper the first subdiagonal,square matrix of n\times n is said to be in lower Hessenberg form  if ai,j=0  for all i,j with j>i+1.and lower Hessenberg matrix is called unreduced if all subdiagonal entries are nonzero.

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Answer:

y=2/3x-13/3

Step-by-step explanation:

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3 years ago
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neonofarm [45]

Answer:

69420

Step-by-step explanation:

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2 years ago
Expression that have an rational product?
Pani-rosa [81]

Step-by-step explanation:

step 1: factor both the numerator and the denominator

step 2: write as on fraction

step 3: simplified the rational expression

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7 0
3 years ago
Sara and Sam are each working on a science project in which they need to research the individual masses of the nine planets (inc
makkiz [27]

Answer:

2000 times

Step-by-step explanation:

Given

Sara:

Mercury = 3.302 * 10^{23

Saturn = 5.685 * 10^{26

Sam:

Mercury = 3.302 * 10^{29

Saturn = 5.685 * 10^{32

To determine the number of times, the mass of Saturn is greater than the mass of Mercury, we simply do the following:

Times = \frac{Saturn}{Mercury}

Using Sara's measurement; this gives:

Times = \frac{5.685 * 10^{26}}{3.302 * 10^{23}}

Apply law of indices

Times = \frac{5.685 * 10^{26-23}}{3.302}

Times = \frac{5.685 * 10^3}{3.302}

Times = 5.685/3.302 * 10^3

Times = 1.72 * 10^3

Approximate

Times = 2 * 10^3

Times = 2000

5 0
3 years ago
Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10
Tanya [424]

Answer:

a) 0.7734

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 101, \sigma = 24

(a) what proportion of children aged 13 to 15 years old have scores on this test above 83 ?

This is 1 subtracted by the pvalue of Z when X = 83. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 101}{24}

Z = -0.75

Z = -0.75 has a pvalue of 0.2266

1 - 0.2266 = 0.7734

The answer is 0.7734

5 0
3 years ago
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