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Anettt [7]
3 years ago
9

given the information in this picture which trigonomic identity can be used to solve for the height of the blue ladder that is l

eaning against the building​

Mathematics
2 answers:
Zarrin [17]3 years ago
5 0

Answer:

sine

sin = o/h

Step-by-step explanation:

The ladder leaning against the building has created a right triangle.

A right triangle is made up of 2 legs (at 90° to each other) and a hypotenuse (longest side).

Trig ratios help us calculate side lengths and interior angles of right triangles:

  • sin(x) = O/H
  • cos(x) = A/H
  • tan(x) = O/A

where x is the angle, O = the side opposite to the angle, A = the side adjacent to the angle, H = hypotenuse

From inspection of the diagram, we need to find the hypotenuse (H) and we have been given the angle (x) and the side opposite to the angle (O):

Therefore, we can use the trig ratio sin(x) = O/H to determine H:

⇒ sin(47) =50/H

⇒ H = 50/sin(47)

⇒ H = 68.36637305... = 68 ft (nearest foot)

professor190 [17]3 years ago
4 0
  • Perpendicular=50ft=P
  • Hypotenuse=h=?

\\ \tt\hookrightarrow sin\theta=\dfrac{P}{H}

\\ \tt\hookrightarrow sin47=\dfrac{50}{h}

\\ \tt\hookrightarrow h=\dfrac{50}{sin47}

\\ \tt\hookrightarrow h=\dfrac{50}{0.73}

\\ \tt\hookrightarrow h=68.4ft

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Answer:

x>-2

Step-by-step explanation:

The translated inequality to be solved is -3x<6

You divide -3 by both sides which switches the sign because it is negative, there fore the answer is x>-2.

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
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