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hram777 [196]
3 years ago
6

I need help with this please

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

0.02564 hours per dollar, or 1/39 hours per dollar

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How much chromium-51 will be left after 7 months?
Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

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3 years ago
2⁄3 − 1⁄2=<br> Answer as a fraction
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Answer: 1/6

Step-by-step explanation:

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Name the two lines and the transversal that form each pair of angles
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A is a line that intersects two coplanar lines at two distinct points. The diagram shows the eight angles formed by <span>a transversal t and two lines / and m.
</span>A transversal that intersects two lines forms eight angles;Corresponding angles,Alternate exterior angles, Alternate interior angles,Consecutive exterior angles, Consecutive interior angles.

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3 years ago
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Please help no links or ill report
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Step-by-step explanation:

the answer is 105

?=1/2(UJ+ST)arc

?=1/2(50+160)

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7 0
3 years ago
Sofia takes 10mg of a medicine whose concentration in blood decreases by a factor of one half every day. Let t be the number of
bazaltina [42]

Answer:  Medication in Lexi's system on day t becomes,

L=10.625(\frac{1}{2})^{t-4}

Step-by-step explanation:

Since we have given that

Initial amount Sofia takes of a medicine = 10 mg

Concentration in blood decreases by a factor of one half every day.

So, it becomes,

S=10(\frac{1}{2})^t\\\\here,\text{ t denotes number of days}

According to question, four days later, it becomes,

S=10(\frac{1}{2})^4\\\\S=\frac{10}{16}\\\\S=0.625\ mg

We have given that Lexi takes 10 mg of the same medicine.

So, it becomes,

10+0.625\\\\10.625\ mg

Hence, Medication in Lexi's system on day t becomes,

L=10.625(\frac{1}{2})^{t-4}

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