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2 years ago

what is a problem that requires multiplying two decimals to find the answer?product must have two decimal places.

Mathematics

1 answer:

andrew11 [14]2 years ago

4 0

1.72 X 3= 5.16 Hope this helps :)

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The length of a rectangle is three times its breadth if the breadth is decreased by 2 m and breadth increased by 4 m the area of

White raven [17]

Answer:

Let the breadth is x, then the length is 3x.

The area is:

A = lw = 3x*x = 3x²

The breadth is decreased by 2 m:

w = x - 2

The length is increased by 4m:

l = 3x + 4

The area is now:

(x - 2)(3x + 4) = 3x² - 1/3(3x²)
3x² + 4x - 6x - 8 = 2x²
x² - 2x - 8 = 0
x² - 2x + 1 = 9
(x - 1)² = 3²
x - 1 = 3
x = 4

The breadth was 4 m and the length 12 m

8 0

2 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is

Aleksandr-060686 [28]

Answer:

B, D, B, D

Step-by-step explanation:

4 0

2 years ago

Jason is mikes older brother. the sum of their ages is 25. the differnece in their ages is 7 write the system of equation that r

Jet001 [13]

Answer:

Equation 1: m+j=25

Equation 2: j=m+5

I hope this helps! Good luck! <3

-YAND3R3

5 0

2 years ago

Jay traveled from Miami to Jacksonville, a distance of 320 miles. He left Miami at 8:00 AM, stopped for lunch for 30 minutes, an

fredd [130]

Distance Rate times Time
320= R 5.25
R= 60.9
R= 61 mph

5 0

3 years ago

A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s

Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

Let $\hat p$ = proportion of students who felt comfortable reporting cheating by their fellow students

Now, point estimate ( $\hat p$ ) is calculated as;

$\hat p=\frac{X}{n}$

where, X = number of students who answered yes = 1,344

n = number of students surveyed = 2,800

So, Point estimate ( $\hat p$ ) = $\frac{1,344}{2,800}$

= 0.48 or 48%

5 0

3 years ago