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2 years ago

(7+x)^2whats the answer?

Mathematics

1 answer:

lianna [129]2 years ago

4 0

Answer:

$(7+x)^2=x^2+14x+49$

Step-by-step explanation:

I'm guessing you are wanting to expand the expression?

$(7+x)^2=(7+x)(7+x)=(7)(7)+(7)(x)+(x)(7)+(x)(x)=49+7x+7x+x^2=x^2+14x+49$

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Answer:

AC = 6

Step-by-step explanation:

y is the dimension of the horizontal segment (see the attached image).

The hypotenuses are the same dimension, so:

(x+4)^2=(x/2)^2+y^2

(3x-8)^2=(x/2)^2+y^2

So,

(x+4)^2 = (3x-8)^2

x+4 = 3x-8

x-3x = -8-4

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And x is the dimension of the segment AC.

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3 years ago

A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly

earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

A survey showed that 77% of us need correction, hence p = 0.77.

13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

$P(X \geq 12) = P(X = 12) + P(X = 13)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299$

$P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334$

Then:

$P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163$

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

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2 years ago