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ivolga24 [154]
2 years ago
12

1. Sharon deposits $6000 into an account with a 2.4% interest rate that is compounded monthly. How much will she have next year?

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Mathematics
1 answer:
mojhsa [17]2 years ago
4 0
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Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor
Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

the lengths of the sides of BRAD are:

\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}

The lengths of the sides of KELY are:

\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}

Each side of KELY is twice the length of the corresponding side on BRAD.  This makes the ratio of the sides 2:1 and the figures are similar.

8 0
3 years ago
Read 2 more answers
Help find domain and range
kolezko [41]

Answer:

d: 4 r:5

Step-by-step explanation:

for domain the x coordinates doesn't go over -2 on the left or 2 on the right so if u add the units of the space in between it's 4 since 2- (-2)=4

for the range, the y coordinates never goes over 3 or -2 so range is 5 is u add the units in between

I hope that makes sense!

4 0
2 years ago
Help..................
Trava [24]
-9 is the slope of the line.
7 0
3 years ago
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Write an equation that describes each line in slope intercept form........slope= 4 y-intercept=-3
LenaWriter [7]
I’m pretty sure it’s y=4x-3
7 0
2 years ago
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A water balloon is tossed into the air with an upward velocity of 25ft/s. Its height H(t) in ft after t seconds is given by the
FinnZ [79.3K]
19. It notes or hints to using the quadratic formula because the equation can not be solved by factoring alone. Thus you must use the quadratic formula.
A=-16 B=25 C=3
It is so hard to type a normal equation let alone one of the quadratic formula so I will just attach a picture instead.
However you will end up getting two roots/zeros/x-intercepts of -0.11 and 1.67.
However since it is an application question asking for answers only in the first quadrant you must choose the positive x-intercept.
Therefore the water balloon will land at 1.67 seconds.

20. This question is very simple as it asks you to find a height at a given time. You simply put the given time (1second) into the equation and get your answer.
h=-16(1)^2+25(1)+3
h=12

Also don't mind my little scribble there. :)

8 0
3 years ago
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