Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
1 answer:
Answer:
It is symmetric about x- axis
The graph is not symmetric along the y - axis
It is not symmetric about the origin
Step-by-step explanation:
We can easily know the solution to your problem by graphing the equation
r(θ) = 2*cos (5*θ)
Please, see attached image
The graph is symmetric about the x axis if
r(θ) = r(-θ)
r(θ) = 2*cos (5*θ) = 2*cos (-5*θ) = r(-θ)
Since the cosine is an even function.
It is symmetric about x- axis
The graph is not symmetric along the y - axis, because
r(θ) ≠ r(π-θ)
It is symmetric about the origin if
r(θ) = r(π+θ)
But, since,
r(θ) = 2*cos (5*θ) ≠ 2*cos (5*(θ+π)) = 2*cos (5*θ+5*π)
It is not symmetric about the origin
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Answer:
18,500 , 1 , 1.03
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
f(t) =18,500(1.03)^t
1st blank:
19,055
1.03
3
18,500
2nd blank:
t years
2 years
3 years
1 year
3rd blank:
19,055
3
18,500
1.03
My answer:
Given that: f(t) =18,500*
1st blank:
Initial value when t = 0, so we have:
f(0) =18,500*
So we choose D for 1st blank
2nd and 3rd blank:
Because it's an exponential function f(t) =18,500* , with every value of t increment f(t) increase by a factor of 1.03 . So Every 1 year the number of students who enroll at the university increases by a factor of 1.03
=> 2nd blank: 1
=> 3rd blank: 1.03
Hope it will find you well.
Answer:
This the expression -3*sqrt(3) or "-3 times the square root of 3"
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Work Shown:
Factor each term inside the square root so that a perfect square is one of the pieces. Then break up the roots and simplify as shown below.