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Alex_Xolod [135]
3 years ago
13

Solve the following: a) 4x-1 / 2= x+7 b) 3x + 2 = 2x + 13 /3

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

a) 2.5

b)2.33

Step-by-step explanation:

a)

4x-\frac{1}{2}= x+7

Bring the numerals to the right hand side and the x terms to the left hand side

4x-x=7+\frac{1}{2}

Simplify

3x=\frac{15}{2}

Divide 3 on both sides, to get x

x=\frac{5}{2} =2.5

b)

3x+2=2x+\frac{13}{3}

Bring the numerals to the right hand side and the x terms to the left hand side

3x-2x=\frac{13}{3}-2

Simplify

x=\frac{7}{3} =2.33

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2 years ago
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
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Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
1/7-3(3/7 n - 2/7) pleaseeee
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Answer:

1- 9n/7

Step-by-step explanation:

I hope i helped! :)

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3 years ago
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