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Jet001 [13]
3 years ago
15

Pleaseeeeee help me pleaseeeeeeeeeee

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

The answer is none of the lines intersect each other, because they are at the same slope, and they do not have a different slope for the lines to be intersected.

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Solve 12x+6>9x+12 please​
Inga [223]

Answer:

x > 2 is your answer.

Step-by-step explanation:

Isolate the variable, x. Treat the > sign as an equal sign, what you do to one side, you do to the other.

First, subtract 9x & 6 from both sides.

12x (-9x) + 6 (-6) > 9x (-9x) + 12 (-6)

12x - 9x > 12 - 6

Simplify.

12x - 9x > 12 - 6

3x > 6

Isolate the variable (x). Divide 3 from both sides.

(3x)/3 > (6)/3

x > 6/3

x > 2

x > 2 is your answer.

~

7 0
4 years ago
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If h(z)=13z2–30z+27, use synthetic division to find h(3).
Blababa [14]

Answer:

h=13z-30+ 27/z

Step-by-step explanation:

4 0
3 years ago
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an unopened can of iced tea contains 350 cubic centimeters of liquid. if the van is 5 inches long and has a .8 inch diameter, wh
MariettaO [177]

the can is 5 inches tall, so its height is 5 inches, so 3 inches off 5 inches that'd be 3/5.

the can has a diameter of 0.8 inches, meaning it has a radius of half that, or 0.4 inches.

if say the volume of iced-tea is V, how much is 3/5 of V?  well, is just their product.


\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=0.4\\ h=5 \end{cases}\implies V=\pi (0.4)^2(5)\implies V=0.8\pi \\\\\\ \stackrel{\textit{and 3/5 of that will be}}{\cfrac{3}{5}\cdot 0.8\pi }\implies V\approx \stackrel{in^3}{1.51}

3 0
3 years ago
The vertices A(-2,-1), B(-3, 2), C(-1, 3), and D(0, 0) form a parallelogram. The vertices A'(-1, -2), B'(2, -3), C'(3,-1),
attashe74 [19]

Answer:

A is correct.

Step-by-step explanation:

The rule for this transformation is that (x,y) will become (y,x) if it flips over y=x OR the y-axis and the x-axis.

5 0
3 years ago
Find the radius and height of a cylindrical soda can with a volume of 256cm^3 that minimize the surface area.
Shtirlitz [24]

Answer:

A) Radius: 3.44 cm.

Height: 6.88 cm.

B) Radius: 2.73 cm.

Height: 10.92 cm.

Step-by-step explanation:

We have to solve a optimization problem with constraints. The surface area has to be minimized, restrained to a fixed volumen.

a) We can express the volume of the soda can as:

V=\pi r^2h=256

This is the constraint.

The function we want to minimize is the surface, and it can be expressed as:

S=2\pi rh+2\pi r^2

To solve this, we can express h in function of r:

V=\pi r^2h=256\\\\h=\frac{256}{\pi r^2}

And replace it in the surface equation

S=2\pi rh+2\pi r^2=2\pi r(\frac{256}{\pi r^2})+2\pi r^2=\frac{512}{r} +2\pi r^2

To optimize the function, we derive and equal to zero

\frac{dS}{dr}=512*(-1)*r^{-2}+4\pi r=0\\\\\frac{-512}{r^2}+4\pi r=0\\\\r^3=\frac{512}{4\pi} \\\\r=\sqrt[3]{\frac{512}{4\pi} } =\sqrt[3]{40.74 }=3.44

The radius that minimizes the surface is r=3.44 cm.

The height is then

h=\frac{256}{\pi r^2}=\frac{256}{\pi (3.44)^2}=6.88

The height that minimizes the surface is h=6.88 cm.

b) The new equation for the real surface is:

S=2\pi rh+2*(2\pi r^2)=2\pi rh+4\pi r^2

We derive and equal to zero

\frac{dS}{dr}=512*(-1)*r^{-2}+8\pi r=0\\\\\frac{-512}{r^2}+8\pi r=0\\\\r^3=\frac{512}{8\pi} \\\\r=\sqrt[3]{\frac{512}{8\pi}}=\sqrt[3]{20.37}=2.73

The radius that minimizes the real surface is r=2.73 cm.

The height is then

h=\frac{256}{\pi r^2}=\frac{256}{\pi (2.73)^2}=10.92

The height that minimizes the real surface is h=10.92 cm.

7 0
4 years ago
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