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krok68 [10]
3 years ago
7

WILL GIVE ALOT OF POINTS HELP FAST One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant

rate from 8 p.m. to midnight. At midnight the temperature was -16.8 degrees. What was the temperature at 9 p.m.?​
Mathematics
2 answers:
yarga [219]3 years ago
8 0

Answer:

4.4

Step-by-step explanation:

I asked google and she said this was right

den301095 [7]3 years ago
4 0

Answer:

4.4

Step-by-step explanation:

16.8 was for 4 hour

divide 4 by 16.8

you get 4.2 per hour

so you need 1 hour

1 hour would be 4.2

temp would be -4.2 at 9pm

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What's the value? A.-20 B.-4 C.4 D.20
ale4655 [162]

Answer:

<h2>-4</h2>

Option B is the correct option.

Step-by-step explanation:

{(4 - 2)}^{3}  - 3 \times 4

Subtract the numbers

=  {(2)}^{3 } - 3 \times 4

Multiply the numbers

=  {(2)}^{3}  - 12

Evaluate the power

= 8 - 12

Calculate the difference

=  - 4

Hope this helps..

Best regards!!

4 0
3 years ago
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How many numbers bewteen 50 and 150 have at least one digit that is 2
mr Goodwill [35]

Answer:

52 62 72 82 92 102 112 120 121 122 123 124 125 126 127 128 129 132 142

there are 19.

Step-by-step explanation:

6 0
3 years ago
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We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
3 years ago
The formula for converting a temperature from degrees Fahrenheit to degrees Celsius is C = (F - 32). What is 86°F in °C?
Vadim26 [7]

Answer:

A

Step-by-step explanation:

(86°F − 32) × 5/9 = 30°C

7 0
3 years ago
3. Factor the following trinomial. x^2 - 15x + 56.
makkiz [27]

Answer:

(x-7) (x-8)

Step-by-step explanation:

Break the expression into groups:

= x(x-7) -8(x-7)

Factor out x from:

x^2-7x     x(x-7)

Factor out -8 from -8x+56:

-8(x-7)

=x\left(x-7\right)-8\left(x-7\right)

8 0
2 years ago
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