Create an equation that has solutions 1 and -1. Leave your equation in factored form!

Mathematics

2 answers:

choli [55]3 years ago

8 0

Answer:

(x-1)(x+1)=0

Step-by-step explanation:

WINSTONCH [101]3 years ago

3 0

If the factors are a and b then we can create the equation as :

$(x-a)(x-b)=0$

Here we are given the solutions as 1 and -1.

Let us plug them in the above equation and try to make an equation using it.

let a=1 and b=-1

So we have,

$(x-1)(x-(-1))=0$

Simplifying,

$(x-1)(x+1)=0$

Answer:

The equation with solutions 1 and -1 is:

$(x-1)(x+1)=0$

You might be interested in

Given M is the midpoint ABA. The coordinate of A are (-4,2) and the cordinates of M are (1,1). Find the coordinate of B. Choose

4vir4ik [10]

Answer:

The coordinate of B is (6,0)

Step-by-step explanation:

Given;

coordinate of A = (-4,2) = (x₁, y₁)

coordinate of M = (1,1)

let coordinate of B = (x₂, y₂)

Mid-point is given by;

$M = \frac{X_1 + X_2}{2} , \frac{Y_1 + Y_2}{2}\\\\M= (1,1)\\\\1,1 =\frac{X_1 + X_2}{2} , \frac{Y_1 + Y_2}{2}\\\\ \frac{X_1 + X_2}{2} = 1 ----equation (1)\\\\\frac{Y_1 + Y_2}{2} = 1 -----equation(2)\\\\Solving \ equation(1)\\\\\frac{-4+ X_2}{2} = 1\\\\-4+ X_2 = 2\\\\X_2 = 2+4\\\\X_2 = 6\\\\Solving \ equation(2)\\\\\frac{Y_1 + Y_2}{2} = 1\\\\\frac{2+ Y_2}{2} = 1\\\\2+Y_2 = 2\\\\Y_2 = 2-2\\\\Y_2 = 0\\\\B = (X_2, \ Y_2)\\\\B = (6, \ 0)$