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Free_Kalibri [48]
3 years ago
5

What is the product of (4x + 6 ) and (2x - 5)

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0
(4x+6)(2x-5)

= 8x^2 - 20x + 12x - 30

= 8x^2 - 8x - 30

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Can someone simplify this expression? 14y – 5(3 – 2y) and explain how you got it.
Paraphin [41]
You first expand the brackets so 
14y-15-10y 
then you put the like terms together  so you do 14y-10y= 4y
4y-15 which is the answer
4 0
3 years ago
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Can you help me solve for x?
sergiy2304 [10]

Answer:

x = 12

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

10x-10 = 60 +4x+2

Combine like terms

10x-10 = 62+4x

Subtract 4x from each side

10x-4x -10 = 62 +4x-4x

6x -10 = 62

Add 10 to each side

6x-10+10 = 62+10

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3 0
3 years ago
After driving to a riverfront parking lot, Bob plans to run south along the river, turn around, and return to the parking lot, r
mars1129 [50]

Answer:A) 1.5

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In 60mins his rate would be=60/8=7.5

Let a be the distance he further runs south

2s+3.25

Total distance covered in 50mins=Time=distance/speed=

50/60

50/60=2s +3.25/7.5

Cross multiply

60(2s+3.25)=50×7.5

120s+195=375

120s=375-195

S=180/120

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5 0
3 years ago
Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

3 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Elina [12.6K]

Answer:

It's answers 1 and 3

Step-by-step explanation:

The meeting is not mandatory and only volunteers are participating in the task he wanted, this shows bias and doesn't correctly represent the whole team.

7 0
3 years ago
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