Solution:
- (x² + x – 12)(x² + 10x + 25)
- => (x⁴ + 10x³ + 25x²) + (x³ + 10x² + 25x) + (-12x² - 120x - 300)
- => x⁴ + 10x³ + 25x² + x³ + 10x² + 25x - 12x² - 120x - 300
- => x⁴ + (10x³ + x³) + (25x² + 10x² - 12x²) + (25x - 120x) - 300
- => x⁴ + (11x³) + (23x²) + (-95x) - 300
- => x⁴ + 11x³ + 23x² - 95x - 300
The only term that has a x-variable is "-95x".
The coefficient of x is -95.
Answer:
CBD is 120 degrees
Step-by-step explanation:
x=30
4x30+30+30=180
For this case we have the following functions:
f (x) = 36 + 4x
g (x) = x2 + 15
By matching both functions we have:
f (x) = g (x)
36 + 4x = x2 + 15
Rewriting we have:
x2 + 15 - 4x - 36 = 0
x2 - 4x - 21 = 0
Solving the polynomial we have:
(x-7) (x + 3) = 0
x = -3
x = 7
Taking the positive root we have:
x = 7
Answer:
They will have the same amount of money saved after:
x = 7 weeks
Answer:
This is your answer <( ̄︶ ̄)↗
Step-by-step explanation:
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#hope it helps you..
(◕ᴗ◕)
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient

![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-7%3D1%5Bx-%28-1%29%5D%5Cimplies%20y-7%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%20y%3Dx%2B8%5Cimplies%20%5Cboxed%7B-x%2By%3D8%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7Bx-y%3D-8%7D)
just to point something out, is none of the options, however -x + y = 8, is one, though improper.