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olga_2 [115]
2 years ago
11

Please help me in this question

Mathematics
1 answer:
charle [14.2K]2 years ago
6 0
Number defective=4
number of non-defective=total-defective
=20-4
=16
the questions asked for 1 defective
so we choose only 1 defective from 4 defective items
4C1

and for 1 non-defective
we choose only 1 non-defective from 16 non-defective items
16C1

we choose 2 items from 20 items
so 20C2

answer:
probability= [(4C1) * (16C1)] /(20C2)
=32/95

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jeyben [28]

Answer:

(-1,0) (0,4) (1,0)

Step-by-step explanation:

The turning points are also called the critical points.  It is where the graph changes direction.

They occur at (-1,0) (0,4) (1,0)

7 0
2 years ago
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If f(x) = - x + 4 and g(x) = x ^ 2 - 5 , then f(g(-2))=?
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Answer:

Step-by-step explanation:

using your f(x) I want to show you how to plug in different things itnot he function.

f(x) = -x + 4

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f(m) = -m + 4

f(abc) = -(abc) + 4

f(h(x)) = -h(x) + 4

Does that help?  what if you replaced h(x) with g(x)?  Of course you already have that x so you could make it a little simpler as well.  Let me know if you don't quite get it.

5 0
3 years ago
if the probability of picking a green marble from a bag of green and red marbles is 0.3. if i choose a marble 100 times and repl
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Answer:

30 marbles would be green

Step-by-step explanation:

green chance is 0.3

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7 0
3 years ago
There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

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0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
2 years ago
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hjlf
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In this case we have 2.67 million.  Well a million is equal to 10^6, because 10*10*10*10*10*10=one million.

So in scientific notation you would write:

2.67X10^6
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