This is a quadratic equation with a general equation of ax^2 + bx + c.
The quadratic formula can help to get the roots of the equation. We know the highest degree of that equation is 2; so there will be also two roots.
The quadratic formula is
x = [-b ± √(b^2 - 4ac)] / 2a
With a = 1, b = 7, c = 2,
x = {-7 ± √[(7)^2 - 4(1)(2)]} / 2(1) = (-7 ± √41) / 2
So the two roots are
x1 = (-7 + √41) / 2 = -0.2984
x2 = (-7 - √41) / 2 = 0.2984
This is also another way of factorizing the equation
(x + 0.2984)(x + 0.2984) = x^2 + 7x + 2
Answer:
sin a = 7/25
cos a = 24/25
tan a = 7/24
Step-by-step explanation:
Trig. How wonderful. I get tripped up on these types of problems some times, so I decided to try to help! To start, write out the three ratios.
SOH (sine=opposite/hypotenuse) CAH (cosine=adjacent/hypotenuse) TOA (tangent=opposite/adjacent)
Then, label the triangle with “hypotenuse” “adjacent” and “opposite.” This helps us correctly use and find the raitos. Then, use these ratios to find out the ratios of A!
sin a = 7/25
cos a = 24/25
tan a = 7/24
If needed, just divide the ratios to get their decimal form!
Answer:
<A = 16.82 degrees
Step-by-step explanation:
Tan^-1 = opposite/adjacent
Tan^-1 (13/43) = 16.82 degrees
The Answer: <span>−30<span>x .-.
good luck</span></span>