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Igoryamba
2 years ago
14

3. For what value of x is

Mathematics
1 answer:
liraira [26]2 years ago
7 0

Answer:

3. x=7

4. f(4)= -24

Step-by-step explanation:

2. Since the bases are equal, equate the powers;

2x+3=17

2x=14

x= 14/2

x=7

3. Putting x as 4 in the function

=3(4²) - 4[3(4) + 6]

=3(16) - 4(12+6)

=3(16) - 4(18)

=48 - 72

f(4) = -24

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Suppose SAT Writing scores are normally distributed with a mean of 488488 and a standard deviation of 111111. A university plans
makvit [3.9K]

Answer:

The minimum score required for the scholarship is 644.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 488, \sigma = 111

What is the minimum score required for the scholarship?

Top 8%, which means that the minimum score is the 100-8 = 92th percentile, which is X when Z has a pvalue of 0.92. So it is X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 488}{111}

X - 488 = 1.405*111

X = 644

The minimum score required for the scholarship is 644.

4 0
3 years ago
A random sample of 300 Americans planning long summer vacations in 2009 revealed an average planned expenditure of $1,076. The e
Rufina [12.5K]

Answer:

(1024.69,\ 1127.31)

Step-by-step explanation:

We know that the sample size was:

n = 300

The average was:

{\displaystyle {\overline {x}}}=1,076

The standard deviation was:

\s = 345

The confidence level is

1-\alpha = 0.99

\alpha=1-0.99\\\alpha=0.01

The confidence interval for the mean is:

{\displaystyle{\overline {x}}} \± Z_{\frac{\alpha}{2}}*\frac{s}{\sqrt{n}}

Looking at the normal table we have to

Z_{\frac{\alpha}{2}}=Z_{\frac{0.01}{2}}=Z_{0.005}=2.576

Therefore the confidence interval for the mean is:

1,076\± 2.576*\frac{345}{\sqrt{300}}

1,076\± 51.31

(1024.69,\ 1127.31)

This means that <em>the mean planned spending of all Americans who take long summer vacations in 2009 is between $ 1024.69 and $ 1127.31</em>

3 0
3 years ago
Highland missed 16 out of 78 points on his last test. What letter grade did he earn?
Papessa [141]

The letter grade he got was around a C or a low B.


8 0
3 years ago
Read 2 more answers
An unknown number is not equal to 3.6 but rounds to 3.6 when rounded to the nearest tenth, what could be the number?
dedylja [7]

Answer:

3.55-3.59

Step-by-step explanation:

to round off to the nearest whole number, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.

So numbers that would be rounded off to 3.6 have to have an hundredth value equal or greater than 5

they include

3.55

3.56

3.57

3.58

3.59

3 0
2 years ago
Please help with 14!
pishuonlain [190]

The answer is c because the variable behind the number s are equal

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2 years ago
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