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Sindrei [870]
3 years ago
6

At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while

later, the angle of elevation of the sun has decreased by 12° and the length of the shadow has increased by 95cm. Determine the height of the pole.

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is \theta

Thus, by the question,

tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}

\implies tan\theta = \frac{x}{x}    ( at 3pm the height of shadow = height of the pole)

\implies tan\theta = 1

\implies \theta = 45^{\circ}

Again, according to the question,

When the angle of elevation is   (\theta - 12^{\circ}),

The height of shadow = x + 95,

\implies tan(45-12)^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}x + 95\times tan33^{\circ}=x

\implies tan 33^{\circ}x - x = - 95\times tan33^{\circ}

\implies -0.3505924068 x = - 61.6937213538

x=175.969930202\approx 175.97\text{ cm}

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