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3 years ago

How do you expand (x-4)^2 ?

Mathematics

2 answers:

nexus9112 [7]3 years ago

5 0

Answer:

(x - 4)^2 = x^2 - 8*x + 16

Step-by-step explanation:

(a - b)^2 = a^2 - 2*a*b + b^2

(x - 4)^2 = x^2 - 2*x*4 + 4^2 = x^2 - 8*x + 16

Anastasy [175]3 years ago

4 0

Answer: x^2 - 8x + 16

Let y = x-4

(x-4)^2 = (x-4)*(x-4)

(x-4)^2 = y*(x-4) ... replace one copy of (x-4) with y

(x-4)^2 = x*y - 4*y .... distribute

(x-4)^2 = x*( y ) - 4( y )

(x-4)^2 = x(x - 4) - 4(x - 4) ... replace y with x-4

(x-4)^2 = x^2-4x-4x+16 .... distribute

(x-4)^2 = x^2 - 8x + 16

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Gennadij [26K]

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<h3>Final value : x² -9x - 11</h3>

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x² - 9x - 11 = 0. #times by 5

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#Give me brainliest pls im tired typing all of this

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s344n2d4d5 [400]

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Read 2 more answers