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vova2212 [387]
3 years ago
11

How do you expand (x-4)^2 ?

Mathematics
2 answers:
nexus9112 [7]3 years ago
5 0

Answer:

(x - 4)^2 = x^2 - 8*x + 16

Step-by-step explanation:

(a - b)^2 = a^2 - 2*a*b + b^2

(x - 4)^2 = x^2 - 2*x*4 + 4^2 = x^2 - 8*x + 16

Anastasy [175]3 years ago
4 0

Answer: x^2 - 8x + 16

Let y = x-4

(x-4)^2 = (x-4)*(x-4)

(x-4)^2 = y*(x-4) ... replace one copy of (x-4) with y

(x-4)^2 = x*y - 4*y .... distribute

(x-4)^2 = x*( y ) - 4( y )

(x-4)^2 = x(x - 4) - 4(x - 4) ... replace y with x-4

(x-4)^2 = x^2-4x-4x+16 .... distribute

(x-4)^2 = x^2 - 8x + 16

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Variable y varies directly with variable x, and y = 16 when x = 12. Enter the constant of variation in lowest terms. y = x
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k = 1.33 or 1 1/3

Formula of Direct variation. Where y is equal to the product of the constant of variation times x.

y = kx
16 = k * 12
k = 16/12
k = 1 4/12 = 1 1/3

Constant of variation is 1 1/3 or 1.33.
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An electrician charges a flat service fee to accept a job and an additional hourly rate to complete the job. The amount an elect
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