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Temka [501]
3 years ago
15

2 (h-8)-h = h-16 what is the solution

Mathematics
1 answer:
Svetach [21]3 years ago
6 0
Let's solve your equation step-by-step.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span>Step 1: Simplify both sides of the equation.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span><span>Simplify: (Show steps)</span><span><span>h−16</span>=<span>h−16</span></span>Step 2: Subtract h from both sides.<span><span><span>h−16</span>−h</span>=<span><span>h−16</span>−h</span></span><span><span>−16</span>=<span>−<span>16
</span></span></span>Step 3: Add 16 to both sides.<span><span><span>−16</span>+16</span>=<span><span>−16</span>+16</span></span><span>0=0</span>Answer:<span>All real numbers are solutions.</span>
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wolverine [178]

Answer:

3x^2

Step-by-step explanation:

3x^2 can be factored out of each

-6x^2 = 3x^2(-2)

21x^3 = 3x^2(7x)

6 0
3 years ago
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Y_Kistochka [10]

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Step-by-step explanation:

3x^2+2x+2+(4x2)+5

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Lim<br> x-&gt;infinity (1+1/n)
FrozenT [24]

Answer:

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1

Step-by-step explanation:

We want to evaluate the following limit.


^{ \lim}_{n \to \infty} (1+\frac{1}{n})


We need to recall that, limit of a sum is the sum of the limit.


So we need to find each individual limit and add them up.

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}


Recall that, as n\rightarrow \infty,\frac{1}{n} \rightarrow 0 and the limit of a constant, gives the same constant value.



This implies that,


^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0


This gives us,

^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1


The correct answer is D



5 0
3 years ago
Solve one third plus seven ninths equals blank
ruslelena [56]

Answer:

10/9ths or 1& 1/9

Step-by-step explanation:

1/3 + 7/9 =

× 9/9. × 3/3

9/27 + 21/27 = 30/27

OR 1 & 1/9

5 0
3 years ago
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uranmaximum [27]

Answer:

x=7; NL=12; NP+20

Step-by-step explanation:

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