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3 years ago

13

mark is working at a restaurant . bread is delivered to the restaurant every third day.meat is delivered to the restaurant every

fifth day. if both where delivered today, in how many days will both items again be delivered on the same day

1 answer:

Natasha2012 [34]3 years ago

6 0

In 15 days both items will be delivered on the same day.

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Select the correct answer.

madreJ [45]

Answer:

y=1/2x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-3)/(4-2)

m=1/2

y-y1=m(x-x1)

y-3=1/2(x-2)

y=1/2x-2/2+3

y=1/2x-1+3

y=1/2x+2

4 0

3 years ago

Consider a sequence given by the formula f(n)=3n-1 starting with n=1. Generate the first 5 terms of the sequence

Rufina [12.5K]

Answer:

The first 5 terms are 2, 5, 8, 11, 14.

Step-by-step explanation:

You use the formula to find out each term.
f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
Now to find each term:

n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14

So the first 5 terms are 2,5,8,11,14

5 0

3 years ago

There is no solution to the following system of equations.

sergij07 [2.7K]

Answer:

True

Step-by-step explanation:

We are given that system of equation

x<3

y>3

We have to find that there is no solution of system of equation is true or not.

First we change inequality equation into equality equation

x=3

y=3

When x=0

0<3

It is true equation therefore, the shaded region towards the origin.

When y=0

0>3

It is false equation. Therefore, the shaded region above the origin.

From the graph

There is no solution of system of equation.

Hence, option true is correct.

6 0

3 years ago

write the equation of the line that is parallel to the line y=-5/3x-2 and goes throught the point (-3,1)

max2010maxim [7]

Answer:

y = (-5/3)x - 4

Explanation:

The equation of a line with slope m that goes through the point (x1, y1) is:

$y-y_1=m(x-x_1)_{}$

Additionally, two lines are parallel if they have the same slope.

The slope of the line y = (-5/3)x - 2 is (-5/3) because it is the number beside x.

So, the slope of our line is also -5/3.

Therefore, replacing m by -5/3 and (x1, y1) by (-3, 1), we get that the equation of the line is:

$\begin{gathered} y-1=-\frac{5}{3}(x-(-3)) \\ y-1=-\frac{5}{3}(x+3) \end{gathered}$

Finally, solving for y, we get:

$\begin{gathered} y-1=-\frac{5}{3}x-(\frac{5}{3}\cdot3) \\ y-1=-\frac{5}{3}x-5 \\ y=-\frac{5}{3}x-5+1 \\ y=-\frac{5}{3}x-4 \end{gathered}$

So, the answer is:

y = (-5/3)x - 4

4 0

1 year ago

Which of the following graphs is described by the function given below? <br>y = x2 - 6x-7

Zanzabum

Answer:

A

Step-by-step explanation:

We are given the function:

$\displaystyle y = x^2 - 6x - 7$

And we want to determine its graph.

One of the most important features of a quadratic is its vertex. So, we can start by finding the vertex using the formulas:

$\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)$

In this case, <em>a</em> = 1, <em>b</em> = -6, and <em>c</em> = -7.

Find the <em>x-</em>coordinate of the vertex:

$\displaystyle x = -\frac{(-6)}{2(1)} = 3$

Substitute this back into the equation to find the <em>y-</em>coordinate:

$\displaystyle y(3) = -16$

Therefore, our vertex is at (3, -16).

The only graph whose quadratic's vertex is at (3, -16) is Graph A. Thus, our answer is A.

5 0

3 years ago