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Gennadij [26K]
2 years ago
7

Can someone answer this question and show work. Please I only have this period to do it. It ends at 8:40 please someone do it

Mathematics
1 answer:
Alla [95]2 years ago
5 0

Answer:

4((sqrt5)-2)

Step-by-step explanation:

Factor 2 Sqrt(5)+4 = 8/(2(sqrt5+4))

divide then you get 5/((sqrt5)+1)

4((sqrt5)-2)

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What are the greatest common divisors of these pairs of integers?a. 3⁷. 5³. 7³,2ⁱⁱ.3⁵.5⁹b. 11.13.17, 2⁹.3⁷.5⁵.7³c. 23³ⁱ,23ⁱ⁷d. 4
KatRina [158]

Answer:

a) 3⁵5³.

b) 1

c) 23³

d) 41·43·53

e) 1

f) 1111

Step-by-step explanation:

The greatest common divisor of two integers is the product of their common powers of primes with greatest exponent.

For example, to find gcd of 2⁵3⁴5⁸ and 3⁶5²7⁹ we first identify the common powers of primes, these are powers of 3 and powers of 5. The greatest power of 3 that divides both integers is 3⁴ and the greatest power if 5 that divides both integers is 5², then the gcd is 3⁴5².

a) The greatest common prime powers of 3⁷5³7³ and 2²3⁵5⁹ are 3⁵ and 5³ so their gcd is 3⁵5³.

b) 11·13·17 and 2⁹3⁷5⁵7³ have no common prime powers so their gcd is 1

c) The only greatest common power of 23³ and 23⁷ is 23³, so 23³ is the gcd.

d) The numbers 41·43·53 and 41·43·53 are equal. They both divide themselves (and the greatest divisor of a positive integer is itself) then the gcd is 41·43·53

e) 3³5⁷ and 2²7² have no common prime divisors, so their gcd is 1.

f) 0 is divisible by any integer, in particular, 1111 divides 0 (1111·0=0). Then 1111 is the gcd

5 0
3 years ago
What are the real solutions of the equation x^4= 81?
zmey [24]
Use photomath it’s free
5 0
3 years ago
What is the value of x?
Ksenya-84 [330]

Step-by-step explanation:

\frac{360 - 2(x  +  30)}{2}  = x \\  360 - 2x - 60 = 2x \\ 300 - 4x = 0 \\ 4x = 300 \\ x = 300  \div 4  = 75

4 0
2 years ago
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aleksandrvk [35]
12.53



You have to multiply 1.79 times 6 then add 1.79
3 0
3 years ago
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6(z+9) I need help figuring this out
NNADVOKAT [17]
The answer should be 6z + 54 but I’m not completely positive.
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2 years ago
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