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3 years ago

Find the length of a rectangular lot with a perimeter of 50 feet if the length is five feet more than the width.

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

Width = 10 feet

Length = 15 feet

Step-by-step explanation:

Let the width = x feet

Length = x + 5

Perimeter = 50 feet

2 * ( length + width) = 50

2 * (x+5 + x) = 50

2x + 5 = 50/2

2x + 5 = 25

2x = 25 - 5 = 20

x = 20/2 = 10

Width = 10 feet

Length = 10 + 5 = 15 feet

OleMash [197]3 years ago

5 0

Answer:

The length of a rectangular lot is 15 feet

Step-by-step explanation:

Let the width of rectangle be x

We are given that the length is five feet more than the width.

Length of rectangle = x+5

Perimeter of rectangle = $2(l+b)=2(x+5+x)=2(2x+5)=4x+10$

We are given that perimeter is 50 feet

So, $4x+10=50$

$4x=40$

x=10

So, Length of rectangle = x+5=10+5=15

Hence the length of a rectangular lot is 15 feet

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Answer:

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Given the following angles from the diagram;

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From the diagram

m<5 = m<1 = 55 degrees (corresponding angle)

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Hence;

55 + m<2 = 180

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m<2 = 125degrees

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m<5 = m<8 = 55 degrees (vertically opposite angle)

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Step-by-step explanation:

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mariarad [96]

Comment
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It will look like this to start with
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Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

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