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3 years ago

Find the length of a rectangular lot with a perimeter of 50 feet if the length is five feet more than the width.

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

Width = 10 feet

Length = 15 feet

Step-by-step explanation:

Let the width = x feet

Length = x + 5

Perimeter = 50 feet

2 * ( length + width) = 50

2 * (x+5 + x) = 50

2x + 5 = 50/2

2x + 5 = 25

2x = 25 - 5 = 20

x = 20/2 = 10

Width = 10 feet

Length = 10 + 5 = 15 feet

OleMash [197]3 years ago

5 0

Answer:

The length of a rectangular lot is 15 feet

Step-by-step explanation:

Let the width of rectangle be x

We are given that the length is five feet more than the width.

Length of rectangle = x+5

Perimeter of rectangle = $2(l+b)=2(x+5+x)=2(2x+5)=4x+10$

We are given that perimeter is 50 feet

So, $4x+10=50$

$4x=40$

x=10

So, Length of rectangle = x+5=10+5=15

Hence the length of a rectangular lot is 15 feet

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And replacing we got:

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$