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3 years ago

Find the length of a rectangular lot with a perimeter of 50 feet if the length is five feet more than the width.

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

Width = 10 feet

Length = 15 feet

Step-by-step explanation:

Let the width = x feet

Length = x + 5

Perimeter = 50 feet

2 * ( length + width) = 50

2 * (x+5 + x) = 50

2x + 5 = 50/2

2x + 5 = 25

2x = 25 - 5 = 20

x = 20/2 = 10

Width = 10 feet

Length = 10 + 5 = 15 feet

OleMash [197]3 years ago

5 0

Answer:

The length of a rectangular lot is 15 feet

Step-by-step explanation:

Let the width of rectangle be x

We are given that the length is five feet more than the width.

Length of rectangle = x+5

Perimeter of rectangle = $2(l+b)=2(x+5+x)=2(2x+5)=4x+10$

We are given that perimeter is 50 feet

So, $4x+10=50$

$4x=40$

x=10

So, Length of rectangle = x+5=10+5=15

Hence the length of a rectangular lot is 15 feet

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