Answer: provided in the explanation segment
Step-by-step explanation:
here i will give a step by step analysis of the question;
A: Optimization Formulation
given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5
Objective function: Minimize manufacturing cost (Z)
Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33
s.t
X11 + X12 + X13 + X14 + X15 = 600
X21 + X22 + X23 + X24 + X25 = 1000
X31 + X32 + X33 = 800
X11 + X21 + X31 <= 400
X12 + X22 + X32 <= 600
X13 + X23 + X33 <= 400
X14 + X24 <= 600
X15 + X25 <= 1000
Xij >= 0 for all i,j
B:
Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.
cheers i hope this helps!!
The highest is 3 does this help u?
Answer: $525
Step-by-step explanation:
The formula for Simple interest is calculated as PRT where
P = Principal = $7500
R = Rate = 3.5%
T = Time = 2 years
Interest = PRT
= 7500 × 3.5% × 2
= 7500 × 0.035 × 2
= $525
Answer:
630
Step-by-step explanation:
the value of 7 in the tenths place is 70
the value of 7 in the hundredths place is 700
compare 700 and 70
So 700-70 = 630
<span>8.42 x 10^3
</span>Use PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
Solve exponent first
<span>8.42 x 10^3
</span>8.42 x 1000
Solve the rest
8.42 x 1000
8420
8420 is between
D.) 8400 and 8500