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mr Goodwill [35]
3 years ago
14

(1 point) how many quarters would be required to make a stack as tall as your height?

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

A quarter is 1.75 mm thick. So, to count how many quarter would "fit" in you when vertically stacked, you have to divide your height by the quarter thickness.

For example, my height is 1.70m, which is 1700mm. So, it would take

\dfrac{1700}{1.75} \approx 971

quarters to reach my height.

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247 + 794 is the same as<br> ? + 800
Dmitry [639]
241 + 800 = 1041
247 + 794 = 1041
5 0
4 years ago
Read 2 more answers
Namd the terms in the expression <br><br>3n + 4p + 2 <br>​
Jobisdone [24]
The terms are 3n, 4p, and 2.
4 0
3 years ago
¿por que en los mapas se respeta la misma escala? Ayudenme por favor esta es otra pregunta ¿qué pasaría si una parte del mapa se
7nadin3 [17]

Answer:

Ok, supón que conoces exactamente tu posición en un mapa, y también sabes a donde quieres ir.

Podes ver en ese mapa la distancia entre tu posición y el lugar al que quieres ir, ahora, si la escala del mapa es conocida (por ejemplo 1cm = 1km) y constante, entonces vos podes medir la cantidad de centímetros entre tu posición y tu destino, y multiplicar ese numero por la escala, de esta forma conociendo la distancia real entre tu posición y tu destino.

Ahora, si la escala no es constante, entonces es imposible saber exactamente la distancia entre nuestra posición y nuestro destino, entonces este mapa no sirve realmente para ubicarnos/guiarnos, entonces no funciona como un mapa.

En el caso de que una parte este en una escala y otra parte en otra, en la primera parte un centímetro en el mapa equivaldría a una distancia X en la realidad, y en la otra zona un centímetro en el mapa equivaldría a una distancia Y en la realidad.

Donde X es diferente de Y, ahora, cuando queremos calcular la distancia entre dos lugares tendríamos que saber exactamente en que lugar se da el cambio de escala (para saber si usamos X o Y). Lo que hace que leer este mapa sea bastante mas difícil que leer un mapa normal.

8 0
3 years ago
Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.
DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

Ways = ^nP_r

This gives

Ways = ^4P_3

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

Ways = ^nC_r

This gives

Ways = ^4C_3

Evaluate

Ways = 4

Hence, the number of ways when the choice is not relevant is 4

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
2 years ago
What is number 61 and a step by step explaination please?
astra-53 [7]

1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

\log_b(m)+\log_b(n)=\log_b(mn)

\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

Then

ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to

2/3 <em>x</em> ¹ʹ³ = exp(3)

Now solve for <em>x</em>. Multiply both sides by 3/2 :

3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

3 0
3 years ago
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