We call x the 4 points-worth problems and y the 3 points-worth problems
You know that x+y = 32
4x+3y = 111
You know that the difference from the x and y is 32 so write:
x = 32-y
Substitute at x the value of 32-y
4(32-y)+3y = 111
128-4y +3y = 111
-4y+3y = 111-128
-y = -17
y = 17
The measure of angle ∠ACB is 70°. Then the correct option is C.
<h3>What is the triangle?</h3>
A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.
∠ABC + ∠BCA + ∠CAB = 180°
60° + ∠BCA + 50° = 180°
∠BCA = 180° – 110°
∠BCA = 70°
Then the correct option is C.
The complete question is given below.
Use the diagram showing m || n, as well as the relationships between interior and exterior angles of ΔABC, to answer the questions.
The measure of ABC is 60
The measure of BAC is 50
The measure of ACB will be
a. 50
b. 60
c. 70
d. 120
More about the triangle link is given below.
brainly.com/question/25813512
#SPJ1
Answer:

<h3>
♁ Question : Solve for x</h3>
<h3>♁ Step - by - step explanation</h3>
Move 12x to L.H.S ( Left Hand Side ) and change it's sign
➛
Move 7 to R.H.S ( Right Hand Side) and change it's sign
➛
Subtract 12x from 15x
Remember that only coefficients of like terms can be added or subtracted.
➛
Add the numbers : 2 and 7
➛
Divide both sides by 3
➛ 
➛ 
The value of x is 
✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄
☄ Now, let's check whether the value of x is 3 or not!
<h3>
☥ Verification :</h3>




L.H.S = R.H.S ( Hence , the value of x is 3 ).
✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄
<h3>✒ Rules for solving an equation :</h3>
- If an equation contains fractions ,multiply each term by the L.C.M of denominators.
- Remove the brackets , if any.
- Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
- Simplify and get the single term on each side.
- Divide each side by the coefficient of variable and then get the value of variable.
Hope I helped!
Have a wonderful time ! ツ
~TheAnimeGirl
Answer:
...
against the wind, an airplane travels 3640 km in 7 hours.
with the wind, the same plane travels 6000 km in 6hrs.
...
let speed of plane in still air be x mph
speed of wind be y mph.
..
t=d/r
..
against wind speed = x-y mph
with wond speed = x=y mph
...
3640/(x-y)=7
3640 = 7x-7y
/7
520=x-y.....................1
...
6000/x+y = 6
6000 = 6x+6y
/6
1000=x+y.....................2
...
Add (1) & (2)
2x=1520
/2
x=760 mph speed of plane in still air
...
plug value of x in 2
1000=760+y
100-760=y
240 = y
240 mph speed of wind