Answer:
The length of the side of the triangle is 10 inches.
Step-by-step explanation:
Let p = perimeter of the equilateral triangle
Let P = perimeter of the square
Let s = length of side of the triangle
Let S = length of side of the square
"The perimeter of an equilateral triangle is 6 inches more than the perimeter of a square"
p = P + 6 Equation 1
"the side of the triangle is 4 inches longer than the side of the square"
s = S + 4 Equation 2
We have 2 equations and 4 unknowns. We need two more equations. We use the definition of perimeter to get the other two equations.
For an equilateral triangle,
p = 3s Equation 3
For a square,
P = 4S Equation 4
Substitute p and P of Equation 1 with equations 3 and 4. Then write equation 2.
3s + 4S = 6
s = S + 4
Now we have a system of 2 equations in 2 unknowns. We can solve for s and S. We can use the substitution method. Solve the second equation for S.
S = 4 - s
Substitute S = 4 - s into equation 3s + 4S = 6.
3s + 4(4 - s) = 6
3s + 16 - 4s = 6
-s = -10
s = 10
Answer: The length of the side of the triangle is 10 inches.
The answer is 12cm because area (420) divided bye height (35) gives you the corresponding side 12cm.
Answer:

Step-by-step explanation:
A standard polynomial in factored form is given by:

Where <em>p</em> and <em>q</em> are the zeros.
We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.
First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.
Therefore, we acquire:

Simplify:

Expand the second and third factors:

Hence, our function is now:

It equals 320 when <em>x</em> = 4. Therefore:

Solve for <em>a</em>. Evaluate:

So:

Our third-degree polynomial equation is:

It’s false. it’s +2 not -2
The surface area is 509.4m power of 2? I have absolutely no idea... Maby I'm correct... Probably not. Sorry...