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3 years ago

11

HELP PLEASE. I don't understand this

2 answers:

Alex777 [14]3 years ago

6 0

It would be repeating because 4 divided by 9 is 0.44444 so on so you could type 0.44

Musya8 [376]3 years ago

3 0

Repeating &/&/:$:38$:$;

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Solve the system,{3y=-x_11,x+4y=14

Llana [10]

your answer would be (2,3)

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3 years ago

What property is 10(5+9x) and 10(9x+5)

tatuchka [14]

Answer:

Associative property: The addition or multiplication of a several numbers is the same regardless of how the numbers are grouped. The associative property will always involve 3 or more numbers. The parenthesis groups the terms that are considered one unit.

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3 years ago

andre [41]

Answer:

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2 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago

The ratio of the perimeter of square RSTU to the perimeter of square WXYZ is 1 to 2. The area of square RSTU is 81 square inches

Vlad1618 [11]

The answer would be 25.5 inches.

4 0

3 years ago