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Svet_ta [14]
3 years ago
10

A card was selected at random from a standard deck of cards. The suit of the card was recorded, and then the card was put back i

n the deck. The table shows the results after 40 trials. What is the relative frequency of selecting a heart? a:15% b:25% c:27% d:35% Outcome Club Diamond Heart Spade Number of trials 8 12 14 6
Mathematics
2 answers:
zalisa [80]3 years ago
5 0
C.35%
If you divide the number of hearts drawn by the number of total draws you get your answer.

14/20=0.35
marysya [2.9K]3 years ago
3 0

Answer:

Its 35%

Step-by-step explanation:

I took the quiz on k 12 and got it right

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Pls help it is due today
Tomtit [17]

Answer:

(-3, 5) is C

(0,-2) is  D

(-2, -2) is E

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Depreciation is the decrease or loss in value of an item due to age, wear, or market conditions. We usually consider
kiruha [24]

Answer:

Part A) V(t)=-5,750t+101,250

Part B) \$55,250

Step-by-step explanation:

Part A) Express the value of the bulldozer, V, as a function of how many years old it is, t.

Let

V ----> the value of the bulldozer (dependent variable or output value)

t ----> the number of years (independent variable or input value)

we know that

The linear function in slope intercept form is equal to

V(t)=mt+b

we have the ordered pairs

(0,101,250) and (15,15,000)

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{15,000-101,250}{15-0}

m=-\$5,750\ per\ year ----> is negative because is a decreasing function

The value of b is the initial value

so

b=\$101,250

substitute

V(t)=-5,750t+101,250

Part B) The value of the bulldozer after 8 years is

For t=8 years

substitute the value of t in the linear equation

V(t)=-5,750(8)+101,250=\$55,250

4 0
3 years ago
Please help me. I don't know what the answer is thank you!
nlexa [21]
Hello,

mes angle AEC=(69+105)/2=87
mes angle AED=(74+112)/2=93

Answer A
4 0
3 years ago
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
3 years ago
PLEASE HELP!!!
antiseptic1488 [7]
Woohhh ok so this is how we will go ahead and do this cool thing today for the rest of the week
5 0
3 years ago
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