Answer:
80000 square meters
Step-by-step explanation:
perimeter + dividing fence = 800
let a = length
let b = width
let c = length of dividing fence
perimeter = 2*a + 2*b
let's say...
c is the same as the length
2a + 2b + c = 800
2a + 2b + a = 800
3a + 2b = 800
area = length*width
area = a*b
area / b = a
3*(area/b) + 2b = 800
3*(area/b) = 800 - 2b
area/b = (800 - 2b)
area = (800 - 2b)*b
To make the area large, we make the right hand side large.
800b - 2b^2
If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.
y = -2x^2 + 800x
y = -x^2 + 400x
0 = x*(-x + 400)
roots are x= 0 and x = 400
vertex is at x, aka b = 200
area at b=200 is (800 - 400)*200 = 80000
and a is area/b... 80000/400 = 200
Answer:
![P= \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]](https://tex.z-dn.net/?f=P%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.5%260.25%260.25%5C%5C0.25%260.5%260.25%5C%5C0.25%260.25%260.5%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
let a, b and c be the type of foods used in trail.
Example matrix combination for (1,1) is (a,a) is 0.5. Another Example for (1,2) is (a,b) is 0.25.
The diagonals are (a,a), (b,b) and (c,c) which means same food in two trails and its probability is 0.5. the rest would be 0.25
Therefore, stochastic matrix would have 3 by 3 matrix such as (a,a), (a,b) .... (c,c)
![\left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right] \\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.5%260.25%260.25%5C%5C0.25%260.5%260.25%5C%5C0.25%260.25%260.5%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
Answer:
25÷2(4+6)-4
Step-by-step explanation:
Parenthesis, multiplication, division, addition, and subtraction
X=-3y+6 That is the answer.
Given:
The two functions are:


To find:
The value of
.
Solution:
We have,


We know that,


![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)

Therefore, the value of
is 2401.