If $2000 is invested at 4% per annum compounded semiannually, how much is in the account after 8 years?

Solve for x. x / 4 ≥ - 8

MariettaO [177]

Answer:

$x \geqslant ( - 32) \: \: \: \: or \: \: \: \: ( - 32) \leqslant x$

Step-by-step explanation:

$\frac{x}{4} \geqslant - 8 \\ x \geqslant - 8 \times 4 \\ x \geqslant (- 32) \\$

3 0

3 years ago

Need help !!!!!!!!!!!!!!!!!!!!!!!

stich3 [128]

Answer: " m∠SRW = 95 ° " .
________________________________________________

Since m∠TRV = 95° ;

and: ∠TRV and ∠SRW are vertical angles;

and: we are given: " m∠TRV = 95° " ;

and: vertical angles are congruent;

So, m∠TRV = m∠SRW = 95° .
_______________________________________________

4 0

3 years ago

12.Divide. (x^2+2x+1/x^2-8x+16)/(x+1/x^2-16

lina2011 [118]

For this case we have the following expression:
(x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
Rewriting we have:
(((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
Then, we cancel similar terms:
((x + 1) / (x-4)) / (1 / (x + 4))
Rewriting:
((x + 1) (x + 4)) / (x-4)
Answer:
((x + 1) (x + 4)) / (x-4)

3 0

3 years ago

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

3 years ago

Ƒ(x) = x2 + 2x − 15 to find the solution when ƒ(x) = 0.

lozanna [386]

Answer:

f = 2 + -15x-1 + x

Step-by-step explanation:

Simplifying

f(x) = x2 + 2x + -15

Multiply f (x)

fx = x2 + 2x + -15

Reorder the terms:

fx = -15 + 2x + x2

Solving

fx = -15 + 2x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.

f = -15x-1 + 2 + x

Simplifying

f = -15x-1 + 2 + x

Reorder the terms:

f = 2 + -15x-1 + x

3 0

3 years ago

Read 2 more answers