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VashaNatasha [74]
2 years ago
6

The ticket price for the hockey match was 14.50. The price has increased by 7%. How much is a ticket after the increase

Mathematics
1 answer:
dlinn [17]2 years ago
7 0

Answer:

15.5

Step-by-step explanation:


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A car is moving at 45mph. Once the care starts to break, its speed(s) is related to the number of seconds(t) it spends breaking
lana [24]

Step-by-step explanation:

When the car stops, the speed is zero.

When S = 0, -10t + 45 = 0, t = 4.5.

Hence it will take 4.5 seconds for the car to stop.

8 0
2 years ago
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A cylindrical tank with radius 5 m is being filled with water at a rate of 3 cubic meters per minute. How fast is the height of
sasho [114]

Answer:

Step-by-step explanation:

Let's calculate the volume of the tank per each meter in height.

The volume of a cylinder is πr²h, where h is the height.  

A height of 1 meter in a tank with a radius of 5 meters would hold a volume of:

Vol = (3.14)*(5 meters)^2 *(1 meter)

Vol (m^3) = 78.54 m^3 per 1 meter height.

If the tank were filled at a rate of 3 m^3/min, it would rise at at a rate of:

(78.54 m^3/meter)/(3 m^3/min) = 0.0382 meters/minute [38.2 cm/min

4 0
2 years ago
Please help to find all reasons and statements i ill give brainliest
8_murik_8 [283]

Answer:

sorry I don't know this

what grade topic is this

8 0
2 years ago
Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin
Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

time=\frac{distance}{speed}

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

x - 3 = \frac{distance}{80} \\distance = 80(x-3)   - - - - - (2)

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

50(3+x)=80(x-3)

150 +50x=80x-240\\

Next, collecting like terms:

150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\

dividing both sides by 3:

x =  390÷30 = 13

∴ x = 13 minutes

7 0
3 years ago
What is the value of discontinuity of x^2+8x+4/x^2-x-6? Choices:
Morgarella [4.7K]

Answer:

-2

Step-by-step explanation:

Hello,

First of all, let's check the denominator.

x^2-x-6 \ \ \text{ *** How to factorise it ...? ***}\\\\\text{*** The product of the roots is -6=-2*3 and their sum is 1 ***}\\\\x^2-x-6=x^2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)

Now, let's see the numerator.

x^2+8x+4 \ \text{ *** -2 is not a zero as ***}\\\\(-2)^2+8*(-2)+4=4-16+8=-4\\\\\text{*** 3 is not a zero as ***}\\\\3^2+8*3+4=9+24+4=37\\

So we cannot factorise the numerator with (x+2) or (x-3)

Then, -2 and 3 are the the discontinuities of the expression.

There is only -2 in the list, this is the correct answer.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
2 years ago
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