Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
Answer:
-675
Step-by-step explanation:
The sum can be broken into parts that you know. Here, one of those parts is the sum of numbers 1 to n. That sum is given by n(n+1)/2.

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Another way to do this is to realize the sequence of numbers is an arithmetic sequence with a first term of 65 and a last term of 67-2·75 = -83.
The sum of an arithmetic sequence is found by multiplying the number of terms by their average value. Their average value is the average of the first and last terms.
The average value of those 75 terms is (65 +(-83))/2 = -9, so their sum is ...
75(-9) = -675
He will pay 26.1$ for 8 2/3 pounds of chicken.
Hope this helps!!
Answer: C
Step-by-step explanation:
I’m pretty sure it’s c because x isn’t less than -2. It goes forever in the directions of positive and negative infinity
Here the value of 3 is =3/10
Then 100 fold of 3/10=3/10*100=30
So, the number 26538,532,97436 etc. has that property.