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natima [27]
3 years ago
5

What is the distance between 7 and −11?

Mathematics
1 answer:
marta [7]3 years ago
4 0
The distance between 7 and -11 is 21
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Find AC. PLSSS HELP BRAINLIEST....
MrRissso [65]

Answer:

5.3

Step-by-step explanation:

Cos(68) = adjacent/hypotenuse

Cos(68) = 2/AC

AC = 2/cos(68)

AC = 5.3389343253

AC = 5.3

4 0
3 years ago
Read 2 more answers
How do you solve this ?
TEA [102]

JK=9x-11\\KL=5x+2\\JL=(9x-11)+(5x+2)=(9x+5x)+(-11+2)=14x-9\\\\JK+KL=JL\\\\\text{substitute}\\\\14x-9=10x+7\ \ \ \ |+9\\\\14x=10x+16\ \ \ \ |-10x\\\\4x=16\ \ \ \ |:4\\\\x=4\\\\JK=9x-11\to JK=9(4)-11=36-11=25

4 0
4 years ago
Which answer is a graph for the inequality x>2
seropon [69]
Show me the answers, then i'll help
6 0
3 years ago
a carpenter has been asked to build an open box with a sqaure base. the sides of the box will cost $3 per m^2 and the base will
slamgirl [31]
<h2>Dimension of box is 2 m x 2 m x 1.33 m</h2>

Step-by-step explanation:

Let a be base side and h be the height.

Volume of box, V = a²h

The sides of the box will cost $3 per m² and the base will cost $4 per m². Cost for making is $48.

That is

                 4a² + 3 x 4 x a x h = 48

                 4a² + 12 a x h = 48

                 a² + 3 ah = 12  

                 h=\frac{12-a^2}{3a}

So volume is

                    V=a^2\times \frac{12-a^2}{3a}=4a-\frac{a^3}{3}

At maximum volume we have derivative is zero,

                    dV=4da-3\times \frac{a^2}{3}da\\\\0=4-a^2\\\\a=\pm 2

Negative side is not possible, hence side of square base is 2m.

Substituting in  a² + 3 ah = 12  

                           2² + 3 x  2 x h = 12  

                             h = 1.33 m

Dimension of box is 2 m x 2 m x 1.33 m

5 0
3 years ago
(-2g^3h)(-3gj^4)^2(-ghj)^2
ratelena [41]

QUESTION -

(-2g^3h)(-3gj^4)^2(-ghj)^2

ANSWER -

−18g^7h^3j^10


Hope i helped have a wonderful day..can i get Brainliest please and thank you...


4 0
3 years ago
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