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Fynjy0 [20]
3 years ago
14

Which defines a circle? two rays with a common endpoint a piece of a line with two endpoints a piece of a line with one endpoint

all coplanar points equidistant from a given point
Mathematics
2 answers:
DENIUS [597]3 years ago
7 0

Answer:

D

Step-by-step explanation:

all coplanar points equidistant from a given point

Shtirlitz [24]3 years ago
5 0
Answer: all coplanar points equidistant from a given point

This is another way of saying "the set of all points that are equally distant from a fixed point" (eg: the set of all points 5 units away from some fixed point). The "fixed point" is the center of the circle. The distance from the center to any point on the circle is the radius.
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How many lots of 10 second are there in 10 minutes
Vlad [161]

Answer:

60

Step-by-step explanation:

We can easily solve this by finding out how many 60 seconds are in 10 minutes, and then dividing by 10.

To do that, multiply 60 seconds by 10, since there are 60 seconds in each minute.

60*10=600. There are 600 seconds in ten minutes.

Now, divide by 10.

600/10=60

There are 60 intervals of 10 seconds in 10 minutes.

Hope this helps!

7 0
3 years ago
Which table represents the same relation as the set StartSet (negative 6, 4), (negative 4, 0), (negative 3, 2), (negative 1, 2)
g100num [7]
Negative 4,0 because I know it
5 0
3 years ago
Read 2 more answers
5. Select All equations that have a solution of 2"
Pachacha [2.7K]

Answer:

none of these have a solution of 2.

Step-by-step explanation:

4x+ 15 = 27

x=3

x + 6 =3

x = 3

2(x+5)=18

x = 4

x + 9 = 6

x = -3

if my understanding of what the equations are supposed to be please let me know what they are supposed to be, because with the way they are typed it is hard to tell :)

6 0
3 years ago
What math do sophomore take
dangina [55]
Typically Geometry. But it depends on your level.
8 0
3 years ago
Read 2 more answers
An object is launched straight up into
DiKsa [7]

Answer:

  t ∈ {1, 3}

Step-by-step explanation:

You want to find t such that ...

  h = 27

  27 = -8t^2 +32t +3 . . . . . . substitute the expression for h

  24 = -8t^2 +32t . . . . . . . . . subtract 3

  -3 = t^2 -4t . . . . . . . . . . . . . divide by -8

  1 = t^2 -4t +4 = (t -2)^2 . . . . add 4 to complete the square

  ±√1 = t -2 . . . . . . . . . . . . . . take the square root

  t = 2 ± 1 . . . . . . . . . . . . . . . . add 2

  t = 1 or 3

The object is 27 ft off the ground at t = 1 and again at t = 3.

8 0
3 years ago
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