Answer:
<em>Equation of the parabola x² = -12.56 y</em>
Step-by-step explanation:
<u>Explanation</u>:-
<em>Given Y- intercept ( 0, -3.14)</em>
<em>Given Focus is ( 0 , -a) = ( 0, -3.14)</em>
<em>So a = 3.14 center C(0,0)</em>
<em>The graph of the parabola is downwards and the axis of the parabola is Y-axis.</em>
<em>Equation of the standard parabola x² = -4 a y</em>
<em> x² = -4 (3.14) y</em>
<em> x² = - 12.56 y</em>
<u><em>Conclusion</em></u><em>:-</em>
<em>Equation of the parabola x² = -12.56 y</em>
I think the 40 30 20 should be going up not down like this 20 30 40
Answer:
See below. No image this time.
Step-by-step explanation:
1.
- P(2, 8) → P'(-5, 1), which it went 7 units to the left, and 7 units down. Here is the equation: (x - 7, y - 7).
2.
- R(-4, -9) → R'(-4, -2), which went 7 units up. Here is the equation: (x, y + 7).
3.
- M(10, -3) → M'(3, 4), which went 7 units left, 7 units up. Here's the equation: (x - 7, y + 7).
4.
- K(7, 11) → K'(0, 11), which went 7 units left. Here is the equation: (x - 7, y).
Answer:
<u>y=90x−410</u>
Step-by-step explanation:
in point-slope form, this would be...
y−130=90⋅(x−6)<-----
If you convert this to slope-intercept form this would be...
y=90x−410