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Alex777 [14]
2 years ago
15

Use absolute value notation to represent the distance between x and 8 is no more than 4

Mathematics
1 answer:
ivanzaharov [21]2 years ago
3 0
The distance: use absolute value
Between x and 8: x-8

The distance between x and 8: | x-8 |

“is no more than” means it can be that or be less than that, so use ≤

The distance between x and 8 is no more than 4

| x-8 | ≤ 4
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Step-by-step explanation:

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Determine whether the triangles are similar. If so, what are the similarity statement and the postulate or theorem used?
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The cost of a whole box of chips are $60. I have $48. What percentage of the total cost do I have?
goblinko [34]

Answer:

Percentage of total I have = 80%    

Step-by-step explanation:

Given:

Price of Box = $60

I Have = $48

To Find:

Percentage I have = ?

Solution:

In this question we are just supposed to find out the percentage of the Value we have so

Percentage can be found by the formula

Percentage =\frac{Given Value}{Total}*100%

Now we have the values of all

So putting in the values

Percentage =\frac{48}{60}*100%

                    =\frac{4800}{60}%

                            = 80%

So the Percentage of total cost I have is 80%

Percentage of total = 80%    


4 0
2 years ago
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
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