Answer:
i believe it is c or b
Step-by-step explanation:
Answer:
They're many numbers
Step-by-step explanation:
3.6, 3.7, 3.8, 3.9
61°
Subtract 90 minus 29. You get 61°
Making sense?
The height of the building is 50√3 feet.
Given to us,
Distance between the building and Amar = 50 feet,
Angle between the top of the building and Amar = 60°
We know that the value of tan 60° is √3.
Thus,
![tan\theta=\dfrac{Perpendicular}{Base} \\\\\rm tan\ 60^o =\dfrac{Height\ of\ the\ building}{Distance\ between\ building\ and\ Amar}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cdfrac%7BPerpendicular%7D%7BBase%7D%20%5C%5C%5C%5C%5Crm%20tan%5C%2060%5Eo%20%3D%5Cdfrac%7BHeight%5C%20of%5C%20the%5C%20building%7D%7BDistance%5C%20between%5C%20building%5C%20and%5C%20Amar%7D)
![\sqrt{3} =\dfrac{Height\ of\ the\ building}{50\ feet} \\](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%3D%5Cdfrac%7BHeight%5C%20of%5C%20the%5C%20building%7D%7B50%5C%20feet%7D%20%5C%5C)
![{Height\ of\ the\ building}= {50\ feet}\times\sqrt{3}](https://tex.z-dn.net/?f=%7BHeight%5C%20of%5C%20the%5C%20building%7D%3D%20%7B50%5C%20feet%7D%5Ctimes%5Csqrt%7B3%7D)
Therefore, the height of the building is 50√3 feet.
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You could say 46/60 (both of these fractions can be reduced), but we can find a fraction between 45/60 and 46/60, namely 91/120. And we can find another between 45/60 and 91/120, and so on ad infinitum.
To answer your question, there is no next fraction. Infinitely many may be found between any two.