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kondor19780726 [428]
3 years ago
9

Sammy was selling tickets for the football game. He sold five more adult tickets than senior tickets and twice as many children'

s tickets than senior tickets. Let s represent the number of senior tickets sold
Mathematics
1 answer:
tester [92]3 years ago
4 0

Sammy was selling tickets for the football game. He sold five more adult tickets (AT) than senior tickets (ST) and twice as many children's tickets (CT) than senior tickets. Let s represent the number of senior tickets sold

ST = AT - 5

CT = 2ST = 2(AT - 5)

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In AMNO, the measure of Z0=90°, the measure of ZM=13°, and OM = 9.6 feet. Find
algol [13]

Answer:

Hypotenuse MN = 10.54 ft (Approx.)

Step-by-step explanation:

Given:

Base OM = 9.6 ft

Angle θ = 13'

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Hypotenuse MN

Computation:

Using trigonometry function

Cos θ = Base / Hypotenuse

Cos 13 = 9.6 / Hypotenuse

0.97 = 9.6 / Hypotenuse

Hypotenuse MN = 10.54 ft (Approx.)

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2 years ago
I need help ASAP please. It's a contest
igor_vitrenko [27]

Answer:

3.25

Step-by-step explanation:

5 0
1 year ago
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For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
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Which of the following equations has both 1 and −3 as solutions?
soldi70 [24.7K]
The answer is B)

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Set factors equal to 0.

x−1=0 or x+3=0

x=1

or

x=−3

5 0
2 years ago
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