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ad-work [718]
2 years ago
12

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different len

gths. For a given applied voltage, how would the joule heat vary with these parameters
Physics
1 answer:
WARRIOR [948]2 years ago
6 0

For the different wires the values given are

For Wire A,  Area=A_{A}, Resistivity=ρ_{A}, Length= L_{A}, Heat=H_{A}, Voltage= V, Time= t, Wire B,  Area=A_{B}, Resistivity=ρ_{B}, Length= L_{B}, Heat=H_{B}

So, H_{A}/ H_{A}=\frac{V^{2} *t}{\frac{ρ(1)*L_{A}  }{A_{A} } }/\frac{V^{2} *t}{\frac{ρ(2)*L_{B}  }{A_{B} } }

Therefore H_{A}/ H_{A}= \frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A}  }

<h3>Heat</h3>

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

Learn more about heat here:

brainly.com/question/21041726

#SPJ4

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An inexperienced researcher runs an experiment and sets his alpha level at .40 because he can't wait to get his firstsignificant
GuDViN [60]

A potential problem is that you are willing to accept a <u>5% </u>chance of being wrong if you reject the null hypothesis.

The significance level is the probability of rejecting the null hypothesis if it is true. For example, a significance level of 0.05 indicates a 5% risk of concluding that there is a difference when there is actually no difference. Rejecting the true null hypothesis results in a Type I error.

The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

Learn more about The potential problems here:-brainly.com/question/21836542

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4 0
1 year ago
The United States is currently a __________.
spin [16.1K]
Your answer is C
A constitutionally limited representative democratic republic [where] . . . the constitution, limits the power of government. We elect representatives, so it's not a pure democracy. But we do elect them by majority rule so it is democratic
4 0
3 years ago
El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La
allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta

En donde:

\omega_{f}: es la velocidad angular final =  2000 rpm = 209,4 rad/s

\omega_{0}: es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.  

Resolviendo la ecuación (1) para α, tenemos:

\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}  

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.  

b) El tiempo transcurrido se puede encontrar como sigue:

\omega_{f} = \omega_{0} + \alpha t

Resolviendo para t, tenemos:

t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0
3 years ago
48.36<br> g.<br> MgSO4 to motes
Julli [10]

Answer:120.3676

Explanation: using the molecular calculator and molar mass of MgSO4. hope this helps!

8 0
3 years ago
At what speed does a clock move if it is measured to run at a rate two-fifths the rate of a clock at rest with respect to an obs
Liono4ka [1.6K]

Answer:

0.44c

Explanation:

We know that

Time interval at speed (ts)= time interval at rest(tr) / gamma

where

gamma = √[1-(v/c)²]

ts = tr / gamma

tr/ts = gamma

But

Ss/Sr = gamma

Where

Sr = clock speed at rest, Ss at speed):

So

√[1-(v/c)²] = 2/5

1 - (v/c)² = 4/25

(v/c)²= 5/25

v/c = √5 / 5

v = 0.444c

4 0
3 years ago
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