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3 years ago

How would you solve for x and y?

Mathematics

1 answer:

Sholpan [36]3 years ago

4 0

Since all of the sides are 15, and there's a right angle, we can assume the triangles are both the same size. So we can halve 15 to get the length of y, which would be 7.5. And here we can use the Pythagorean's Theorem to solve for x, by changing it to c^2-b^2=a^2, and we can fill out 15^2 - 7.5^2 = a^2, or 225 - 56.25 = √173.75, which is about 13.18.

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tresset_1 [31]

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Mode is the number (or in this case, color) that appears the most amount of times.

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3 years ago

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bonufazy [111]

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3 years ago

Simplify: (8t4 + 6 )+(914 – 2ť + 6t? – 6 )

vekshin1

Answer:t

2⋅(17t 2 −2t+6)

Step-by-step explanation:

v(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

Equation at the end of step

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

5 0

3 years ago