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qwelly [4]
3 years ago
8

A furniture store can spend no more than $5,000 on raw materials for recliners. The raw materials cost $5 per square foot of clo

th and $ 10 per foot of wood. To summarize the situation, a worker writes the inequality: 5 x + 10 y ≤ 5,000 , where x is the number of square feet of cloth material and y is the number of feet of wood. Which graph's shaded region shows the possible combinations of raw materials the company can buy? I need the graphing answer

Mathematics
2 answers:
Fofino [41]3 years ago
8 0

Answer:

bottom to the right :)

Step-by-step explanation:

11Alexandr11 [23.1K]3 years ago
7 0

Answer:

The bottom one to the right. It only reaches 1000 and no higher

Step-by-step explanation:


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As x increases without bound, f(x):
yarga [219]

Answer: Choice D) approaches y = -4

"x increases without bound" is another way of saying "x heads off to positive infinity". Visually, you follow the graph curve going to the right. As the graph shows, the curve steadily gets closer to the horizontal line y = -4, but it never actually gets there. This line is the horizontal asymptote.

7 0
3 years ago
Four times a number is greater than 48. what are the possible values for the number?​
Novosadov [1.4K]

Answer:

52 =4x 13

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
2=-7/4+1/4x I need help!!
DochEvi [55]

Answer:

x = 15

Step-by-step explanation:

2 = -7/4 + 1/4x

+7/4  +7/4                 Add 7/4 to both sides

15/4 = 1/4x                Divide both sides by 1/4

15 = x

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3 0
3 years ago
Find a general solution of y" + 8y' + 16y=0.
Misha Larkins [42]

Answer:

The general solution: C_{1}e^{-4x} + xC_{2}e^{-4x}

Step-by-step explanation:

Differential equation: y'' + 8y' + 16y = 0

We have to find the general solution of the above differential equation.

The auxiliary equation for the above equation can be writtwn as:

m² + 8m +16 = 0

We solve the above equation for m.

(m+4)² = 0

m_{1} = -4, m_{2} = -4

Thus we have repeated roots for the auxiliary equation.

Thus, the general solution will be given by:

y = C_{1}e^{m_{1}x} + xC_{2}e^{m_{2}x}

y = C_{1}e^{-4x} + xC_{2}e^{-4x}

6 0
3 years ago
The sum of 30 times (1/3)^(n-1) from 1 to infinity
sergeinik [125]

Let

S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}

Then

\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}

and

S_n-\dfrac13S_n=\dfrac23S_n=1-\dfrac1{3^{n+1}}\implies S_n=\dfrac32-\dfrac1{2\cdot3^n}

and as n\to\infty, we end up with

\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32

So we have

\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45

8 0
3 years ago
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