Looking for the domain and range
1 answer:
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Answer:
Point (0,0)
Step-by-step explanation:
Given the inequality y > 12x – 11.
We will check which of the given options will be applied for the inequality
A) (1,0)
Substitute with x = 1 and y = 0
0 > 12*1 - 11
0 > 1 ⇒ Wrong
So, Point (1,0) is not part of the solution of the inequality.
B) (3,2)
Substitute with x = 3 and y = 2
2 > 12*3 - 11
0 > 25 ⇒ Wrong
So, Point (3,2) is not part of the solution of the inequality.
C) (1,1)
Substitute with x = 1 and y = 1
1 > 12*1 - 11
1 > 1 ⇒ Wrong
So, Point (1,1) is not part of the solution of the inequality.
D) (0,0)
Substitute with x = 1 and y = 0
0 > 12*0 - 11
0 > -11 ⇒ True
So, Point (0,0) is part of the solution of the inequality.
Also, see the attached figure which represents the given inequality
The shaded area represents the solution of the inequality, and we can note that point (0,0) is part of the solution of the inequality
The function is 
.
To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:
f(1)=1-11+36-36, not 0
f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).
Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).
We can also try some other factors of 36. Indeed we can check that
f(3)=27-99+108-36=135-135=0,
and
f(6)=216-396+216-36=0.
Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.
This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).
Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6.
The y-intercept is f(0), which is -36.
Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly,
we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.
Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity,
and it goes to minus infinity as x goes to - infinity.
To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:
f(1)=1-11+36-36, not 0
f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).
Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).
We can also try some other factors of 36. Indeed we can check that
f(3)=27-99+108-36=135-135=0,
and
f(6)=216-396+216-36=0.
Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.
This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).
Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6.
The y-intercept is f(0), which is -36.
Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly,
we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.
Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity,
and it goes to minus infinity as x goes to - infinity.
Answer:
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let h represent the hypotenuse, then
h² = 5² + ( )² = 25 + 2 = 27 ( take the square root of both sides )
h = ← exact value