Does not exist, since the graph of cosine is continuous between the intervals [-1,1]. You do not know where it will be when it “reaches” infinity
I can’t do math right now but plug it into a graphing calculator (after pressing the “Y=“ button) and then press graph and you should be good
Answer:
745
Step-by-step explanation:
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².
To find the perimeter of each, we add the area of all sides. For the first figure, the missing sides are 1 cm and 6 cm. To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.
For the second figure, the missing sides are 4 cm and 3 cm. To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.
For the third figure, the missing sides are 3 cm, 3 cm and 8 cm. To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.
For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm. To find the area, we have two squares whose dimensions are 10x10.
For the fifth figure, the missing sides are 3 cm and 9 cm. To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
Answer:
Future value of land = 25,000[1.04]³⁰
Future value of land = $81,084 (Approx.)
Step-by-step explanation:
Given:
Purchase cost of land in 1970 = $25,000
Application rate = 4% per year
Find:
Price of land in 2000
Computation:
Number of year = 2000 - 1970 = 30 year
Future value of land = [Purchase cost of land][1+Application rate]ⁿ
F = P[1+r]ⁿ
Future value of land = 25,000[1+4%]³⁰
Future value of land = 25,000[1+0.04]³⁰
Future value of land = 25,000[1.04]³⁰
Future value of land = 25,000[3.24339]
Future value of land = 81,084.75
Future value of land = $81,084 (Approx.)
