Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
The solution for s in the given equation is 
The question seems to be incomplete
Here is the complete question:
Solve for s in this equation 
Depreciation.
To solve for s, that means we should make s the subject of the equation
From the given equation,
To solve for s, first multiply both sides by n to clear the fraction
We get
Then,
Now, add s to both sides
Then, subtract nD from both sides
∴
Hence, the solution for s in the given equation is
Learn more here: brainly.com/question/21406377
Answer:
<em>P=760</em>
Step-by-step explanation:
Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.
Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).
This shape has sides that are parallel to both axes.
To calculate the perimeter we find the length of two sides.
The distance from A to B is the difference between their y-axis:
w=112-(-3)=115
The distance from A to C is the difference between their x-axis:
l=2-(-212)=215
It's evident this is not a square but a rectangle. The perimeter is
P=2w+2l=330+430
P=760
What thats so long sjsusjdjss
Remark
You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.
Problem One
The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.
<em><u>Triangle</u></em>
Area = 1/2 * b * h
base = 16 cm
h = 10 - 4 = 6
Area = 1/2 * 16 * 6
Area = 48
<em><u>Area of the Rectangle</u></em>
Area = L * W
L = 16
W = 4
Area = L * W
Area = 16 * 4
Area = 64
<em><u>Total Area</u></em>
Area = 64 + 48
Area = 112 of both figures <<<< Answer
