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Mars2501 [29]
3 years ago
7

What is the solution to this equation x/-5 = -6

Mathematics
2 answers:
9966 [12]3 years ago
5 0

Answer:

x = 30

Step-by-step explanation:

x/-5 = -6

x = -6(-5)

x = 30

SIZIF [17.4K]3 years ago
5 0
X=30 mskakakakamkakakakak
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In a four digit number, the digit in thousand’s place in 4 and the digit in the one’s place is twice that in the thousand’s plac
ale4655 [162]

Answer:

Step-by-step explanation:

As 4 is accumulated by thousands place

And ones place is 4 into 2/twice

And hundreds place accumulates zero

And tens place is 4 - 0=4

The no is

4048

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3 years ago
Ravi needs to buy some pencils. Brand A has 36 pencils for $8.52. Brand B has a pack of 48 pencils for $9.98. Find the unit pric
Aliun [14]

For this question you would divide $8.52 by 36 pencils to get about $0.24 per pencil for brand A rounded to the nearest cent. Then divide $9.98 by 48 pencils to get about $0.21 per pencil for brand B rounded to the nearest cent.

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3 years ago
Complete the table.<br> Thank you
lesya692 [45]

Answer:

16.5

Step-by-step explanation:

The relationship between x and y is that y is just x+3.5. So if x is 13, then y is 13+3.5 which is 16.5.

7 0
2 years ago
Read 2 more answers
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0
3 years ago
Helpppp me pls! What is the lenght of AC?
Crazy boy [7]

Step-by-step explanation:

Bc is also 20 answer is 400

7 0
3 years ago
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