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LUCKY_DIMON [66]
2 years ago
10

Alina measured a distance to be 2.18 miles. what is the margin of error? 2.1 miles to 2.2 miles 2.175 miles to 2.185 miles 2.185

miles to 2.195 miles 2.2 miles to 2.3 cm
Mathematics
1 answer:
Gre4nikov [31]2 years ago
7 0

Answer:

  (b)  2.175 miles to 2.185 miles

Step-by-step explanation:

When a value is rounded, the original "exact" value is presumed to be within 1/2 of the value of one least-significant unit of the rounded number.

<h3>Application</h3>

A rounded value of 2.18 has a least-significant digit with a place value of 0.01 units. Half that value is the "margin of error". That is, the range of numbers that would be rounded to 2.18 is ...

  2.18-0.005 ≤ x < 2.18+0.005

  2.175 ≤ x < 2.185 . . . . miles

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Which is not an equation of the line going through (3, -6) and (1, 2)?
777dan777 [17]

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B, C

Step-by-step explanation:

The equation of a line can be given by y -y₁= m(x -x₁), where m is the slope. This is also known as the point-slope form.

\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }

Slope of the line

=  \frac{2 - ( - 6)}{1 - 3}

=  \frac{2 + 6}{ - 2}

= \frac{8}{ - 2}

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<em>Substitute m= -4 into the equation:</em>

y -y₁= -4(x -x₁)

<em>Substitute a pair of coordinates into (x₁, y₁):</em>

Let's start by substituting (1, 2).

y -2= -4(x -1)

This gives us the same equation as D, making D an incorrect option. Note that the question asks for which is not the correct equation.

Let's change the above into the slope-intercept form, where by y is the subject of formula.

<em>Start by expanding the right-hand side:</em>

y -2= -4x +1

<em>+</em><em>2</em><em> on both sides:</em>

y= -4x +3

This equation is not the same as C. C is thus the correct option.

Let's check for options A and B.

The equation in option B is not the correct equation either as they have substituted (2, 1) instead of (1, 2) into (x₁, y₁). Thus, option B is also correct.

y -y₁= -4(x -x₁)

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y -(-6)= -4(x -3)

y +6= -4(x -3)

This is the same as option A, making option A incorrect too.

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2 years ago
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