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Aliun [14]
3 years ago
8

A paper company ships one 110.4 tons of paper in four trucks if Eachtruck carries the same weight how many tons of

Mathematics
2 answers:
Lerok [7]3 years ago
7 0
Divide total weight by number of trucks:

110.4 / 4 = 27.6 tons per truck
zhannawk [14.2K]3 years ago
6 0
You said that "each truck carries the same weight".
This means that the shipping manager DIVIDED the paper equally among the four trucks.     Does that give you any ideas, hmm ?
How about DIVIDING the 110.4 tons into 4 equal parts, thenput one part on each truck.
110.4 tons   DIVIDED by  4  =  27.6 tons
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hoa [83]
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= 3/(5x) + 5x²/5x
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4 0
3 years ago
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5/6+2/9= in simplest form I NEED this plz help
tensa zangetsu [6.8K]

Answer: 1  1/18

Step-by-step explanation: 5/6 + 2/9 I know this might seem like common, but <em>the </em><em>Numerator is the top number of a fraction</em><em> and the </em><em>Denominator is the bottom a fraction.</em> When the numerator and the denominator are the same such as 5/5 the fraction equals one (I know its real fancy). When you're multiplying a fraction that equals on by another fraction its really just multiplying by a fancy looking 1 that's disguised as a fraction such as  5/5. If you simplify it it goes to the fraction it was as long it was simplified to the max  (5/5 x 1/2 = 5/10= 1/2)

  • First, you need to find a like denominator,  which is 18
  • Then, you got to multiply each fraction to make them have common denominators ...multiply 5/6 by 3/3  ( 3/3 is just  a fancy way of saying one) 5/6 x 3/3 = 15/18....multiply  2/9 by 2/2 (which is just another fancy way of saying one ) 2/9 x 2/2=4/18
  • Next you add them but only the numerator  15/18 + 4/18 = 19/18
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6 0
3 years ago
A 4f by 5ft dock is anchored in the middle of a lake. The bow of a boat is tied to a corner of the dock with a 5ft rope as shown
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3 years ago
A trapezoid is a polygon that has exactly one pair of parallel sides.
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4 0
3 years ago
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A​ true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn
Makovka662 [10]
<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

H_0: p=0.50

H_a: p>0.50 , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : \dfrac{52}{80}=0.65

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68

P-value : P(z>2.68)=0.0037   [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

8 0
3 years ago
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